Frequent Questions about our Solver

The problem

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What are the value or values that makes the denominators zero?

Answer provided by our tutors

There are several ways to visualize what question is being asked... Any algebraic expression set equal to zero allows you to solve for "zeros".  That particular equation, however, only yields imaginary roots.  I can manually manipulate into the form "2x^2 + 15x + 29 =0" and solve for imaginary roots for 'x':

https://doyourmath.com/redirect/174/3f55d74973c0ac77c742ad7033610d42?q=c%3Dsolve%26v1%3D2x%25255E2%252B15x%252B29%25253D0%26v2%3Dsolve%26v3%3Dx%3C%2Fp%3E

The equation has two illegal expressions when the 'natural solution' is x=-4 since the denominators -4+4=0 and division by zero is not valid. 

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