Frequent Questions about our Solver
why are there no steps for this solution?
Answer provided by our tutors
Yes, that particular polynomial expression is not readily factored other than manual "try" methods. The factors which do evenly divide the original polynomial are "(x-2)" and "(x+2)". This begins with a visual inspection of the polynomial and identifying the prime factors and then I like to use Algebrator's Polynomial Wizard titled "Long division" to verify that an attempted factor does evenly divide the polynomial (leaving no remainder).
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For example, choosing (x+5) as a factor does leave a remainder, yet (x-2) does evenly divide the polynomial.
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