The problem
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are you able to show the calculation of this problem
Answer provided by our tutors
The graph for the linear equation 'y = 3x + 1' is a straight line.
Thus, we only need two points from the line to plot.
For 'x =0' we get
y = 3*0 + 1
y = 1
One point from on line is (0, 1).
For 'y = 0' we get
0 = 3x + 1
x = -1/3
Second point on the line is (-1/3, 0).
Now, we can plot the graph by drawing line that goes trough (0, 1) and (-1/3, 0):