FACTORING QUADRATIC QUESTION .

Hello , in the equation 2x^2 -2xy -12y^2 , the calculator factored to get the 1st step , 2(x^2 - xy -6y^2 ) I understand that .

then it factored to get the 2nd step , 2(x^2 -3xy +2xy -6y^2 ) .

I don't understand how they got the -3xy +2xy in the 2nd step .

I see that they must of said that , 2(x^2 - xy -6y^2 ) was in quadratic format .

I see that they must of said in regards to the last term , -6y^2 , that

what two numbers multiplied can give me -6 , and when added , can give me xy .

and that would be the numbers -3xy +2xy ...

So , this is my confusion ... 2(x^2 - xy -6y^2 ) I thought that the last term , -6y^2 ,

had to be a constant ( a single number , such as 2, 3, etc ) In order to use the quadratic

format to factor how they just did ... because the quadratic format is

ax2 + bx + c = 0 where c is a number not a term such as -6y^2 .

Thank you .