The problem
Click to see the original problem
Fill in the restrictions on the variable.
Answer provided by our tutors
To find the restrictions you need to set the denominator equal to zero and solve the equation (The solution or solutions are the restricted values.)
In this case we need to solve:
x^2-3x-10 = 0
and
x^2-8x+15 = 0
The solutions for
x^2-3x-10 = 0 are x1 = 5 and x2 = -2
Click here to see the step by step solution
The solutions for
x^2-8x+15 = 0 are x1 = 5 and x2 = 3
Click here to see the step by step solution
The restrictions on the variable are x needs to be other than -2, 3 and 5.