That problem has to be manually worked through, as follows:

identify c^2-b^2 by splitting the product -4(c^2-b^2) into two parts whose sum is 4b

so the factors of -4(c^2-b^2) that sum to 4b are "2a(b+c)" and "2a(b-c)"

-4a^2+4ba+(c^2-b^2)=-4a^2+2a(b+c)+2a(b-c)-(b-c)(b+c)

...factor pairs of terms by grouping:

(b+c)(2a-(b-c))-2a(2a-(b-c))

...pull out a common factor:

(2a-(b-c))(-2a+b+c)

...distribute the '-' into (b-c), giving:

(2a+c-b)(-2a+b+c)