The problem
Click to see the original problem
how do i solve:
Write a quadratic equation with solutions 4 and
-(7/3)? Can us the zero-factor property in reverse.
...... I don't how to plug in this problem with the choices on my screen.
Answer provided by our tutors
The equation is of the form:
(x - p)(x - q) = 0,
where p and q are the roots.
Plug p = 4 and q = -(7/3) into above equation:
(x - 4)(x - (-7/3)) = 0
By expanding the above expression we get:
(x - 4)(x - (-7/3)) = x^2 - (5/3)x - 28/3
Click here to see the expanding.
So the equation is:
x^2 - (5/3)x - 28/3 = 0
Multiply both sides by 3 and you will get the more "elegant" solution:
3x^2 - 5x - 28 = 0