The problem
I'm trying to figure out where I went wrong in solving this equation but can't add it to the algebrator. {-6/5, 9/5}. I'm supposed to figure out the equation. I came up with x^2-3/5x-3/5. Can you help? Thanks
Answer provided by our tutors
Given the set {-6/5,9/5}, those are the zero values for the quadratic equation. Those zero values would set up the monomials for the desired quadratic expression. Since once zero is -6/5, the monomial would be (x+6/5) since (-6/5 + 6/5) equals 0. The other monomial would be (x-9/5) since 9/5-9/5=0.
Those monomials reconstitute the desired quadratic expression by multiplying the monomials together: (x+6/5)(x-9/5). This can be checked by setting the correct expression, x^2-(3/5)x-54/25, equal to zero and solving for the desired zero-values.
