The problem
In first step fr + f . 2 power 3 . y = my How did you get two f's fr + f. 2 power 3 etc.?
I understand you multiplied both sides by r + 8y to get rid of this term on the right hand side, but how did you get two f's on the left hand side
fr + f . 2 power 3 etc
Answer provided by our tutors
First, product distributive property is used:
A*(B + C) = A*B + A*C
In your equation it will be:
f(r + 8y) = f*r + f*8*y
Also, 8 = 2*2*2 = 2^3 but this is not important, you can keep the '8' in the solution instead of '2^3'.
Since we want to solve for 'y' we need to move all the 'y' terms to one side and the rest on the other side. Then we isolate the variable by dividing both sides by 'm-8f'.
You can obtain an explanation for any step by clicking on it. Please note that you cannot click on the very first expression, which is the original problem.