The problem
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need to know which one have no solution
6m<_-36 and m+24>20
-2m<6 and 3m>24
8m+5>_5 and -4m+6<_-10
m+9<8 and -2m>_10
Answer provided by our tutors
Type the systems into 'Algebrator' but instead of 'and' put comma:
6m<=-36 and m+24>20 gives solution m<=-6, m>-4 (click here to see the solving)
Since there is no such m, 6m<_-36 and m+24>20 has no solution.
-2m<6 and 3m>24 gives solution m>8 (click here to see the solving)
Thus -2m<6 and 3m>24 has solution.
8m+5>_5 and -4m+6<_-10 gives solution m>0 (click here to see the solving)
Thus 8m+5>_5 and -4m+6<_-10 has solution.
m+9<8 and -2m>_10 gives solution m<-1 (click here to see the solving)
Thus m+9<8 and -2m>_10 has solution.
So the final answer is: out of the given systems of inequalities, 6m<_-36 and m+24>20 has no solution.