The problem
Click to see the original problem
We are using Knewton during the Virus, Knewton shows the answer to this equation as 290 miles and do your math show 200 mph.
It's 4 5/6x60
Scott drove for 4 5/6 hours @ 69 mph. What distanced did he travel? Is that correct?
Answer provided by our tutors
Let
t = 4 5/6 hours is the time of the travel
v = 60 mph is the average velocity
d = the distance traveled
Since v = d/t we have d = v*t
d = (4 5/6)*60
You are getting the wrong answer because you have typed in:
In order to get the right answer you need to type in:
This way you will get the correct result:
d = 290 mi
Click here to see the step by step solution.