The problem
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what is the vertex equation to find this equation
Answer provided by our tutors
The general quadratic equation is
y = ax^2 + bx + c
You are given
y = x^2 - 1
So, the values for "a", "b" and "c" are:
a = 1
b = 0
c = -1
The vertex is calculated by first finding "x" from the formula "x=-b/2a" and then plugging into the equation "y = x^2 - 1" to find "y".
So,
x = -0/2*1
x = 0
y = 0^2 - 1
y = -1
Thus, the vertex is (0, -1).
You can also read the vertex from the graph