The problem
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you did not provide an explanation as to how you factorised x^2+7xy+12y^2+2x+8y into (3y+x+2) (4y+x) please elaborate
Answer provided by our tutors
x^2 + 7xy + 12y^2 + 2x + 6y
collect the expression in terms of 'x' and look to factor the constant term with respect to 'y':
x^2 + x(7y+2) + (12y^2 + 8y)
factor '4y' out of '12y^2 + 8y':
x^2 + x(7y+2) + 4y(3y+2)
The factors 4y(3y+2) that sum to 7y+2 are x(3y+2) and 4xy:
x^2 + x(3y+2) + 4xy + 4y(3y+2)
factor pairs of terms by grouping:
x(x+4y) + (3y+2)(x+4y)
pull out a common factor, 'x+4y':
(x+4y)(x+3y+2)